Radius of the circle x2+y2-4x+2y-45 0 is

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WebFind the Center and Radius x^2+y^2+4x-2y=-1 x2 + y2 + 4x − 2y = −1 x 2 + y 2 + 4 x - 2 y = - 1 Complete the square for x2 +4x x 2 + 4 x. Tap for more steps... (x+2)2 −4 Substitute (x+2)2 − 4 for x2 +4x in the equation x2 + y2 +4x−2y = −1. (x+2)2 −4+y2 −2y = −1 Move −4 to the right side of the equation by adding 4 to both sides. WebMar 29, 2024 · The equation of the circle is then re-written as; x^2 -4x + 4 +y^2 +2y + 1 = 11 +4 +1. We then factorize the expressions in x and y separately; (x-2)^2 + (y +1)^2 = 16. The center of the circle is thus; (2, -1) The radius is the square root of 16; r = 4. find the attached.

Find the Center and Radius x^2+y^2-4y=0 Mathway

WebA: The given equation of the circle is x2+2x+y2-4y=4 To find: 1) Center of the circle 2)…. Q: find the center and the length of a radius for each circle. x2 + 14x + y2 - 8y + 16 = 0. A: A … WebThe equation of the given circle is x 2+y 2−4x−8y−45=0. (x 2−4x)+(y 2−8y)=45 (x−2) 2+(y−4) 2−4−16=45 (x−2) 2+(y−4) 2=65 (x−2) 2+(y−4) 2=( 65) 2 Thus, the centre of the given circle is (2,4) and radius is 65. Was this answer helpful? 0 0 Similar questions Find the centre and radius of each of the following circle. (x−5) 2+(y−3) 2=20 Medium phytylation

The equation of a circle is x^2 + y^2 -4x + 2y - 11 = 0. What …

WebFeb 3, 2024 · Ans: The required equation of circle is x 2 + y 2 – 4x + 2y – 45 = 0. Example 09: Find the equation of circle having centre at (2, -3) and passing through P(-3, 5) ... Find equation of a circle having centre at (- 4, 0) and radius 5. Ans: x2 + y2 + 8x – 34 = 0 6. Find equation of a circle having centre at (7, 2) and radius 3. Ans: x2 + y2 ... WebFind the Center and Radius x^2+y^2-4x-2y-20=0. x2 + y2 - 4x - 2y - 20 = 0. Add 20 to both sides of the equation. x2 + y2 - 4x - 2y = 20. Complete the square for x2 - 4x. Tap for more steps... (x - 2)2 - 4. Substitute (x - 2)2 - 4 for x2 - 4x in the equation x2 + y2 - 4x - 2y = 20. (x … phy tx delay

Find the center and radius of the circle x^2 + y^2 - 4x - 8y

What is the center and radius of x^2+4x+y^2-6y-3=0? Socratic

WebJan 17, 2024 · radius = 2 Explanation: The standard equation of a circle with centre (a,b), and radius r is: (x − a)2 +(y −b)2 = r2 so for : x2 + y2 +4x − 2y = − 1 we will have to complete the square before we can identify the radius. x2 +y2 + 4x −2y = − 1 x2 +4x + y2 −2y = − 1 (x2 + 4x) +(y2 − 2y) = − 1 (x2 + 4x + 22) − 22 +(y2 − 2y +12) − 12 = −1 WebSep 30, 2016 · Explanation: x2 +y2 − 4x +12y − 36 = 0. Rearrange the terms by grouping the x terms, grouping the y terms, and moving the constant term to the other side. x2 −4xaaa + y2 +12yaaa = 36aaa. Complete the square for x terms and the y terms. To complete the square for the x terms, divide the coefficient of the "middle term" 4x by 2, square the ... phyt\u0027s cosmeticsWebSolution Verified by Toppr x 2+y 2−4x−8y−45=0 ⇒(x 2−4x)+(y 2−8y)=45 ⇒ {x 2−2(x)(2)+2 2}+{y 2−2(y)(4)+4 2}−4−16=45 ⇒(x−2) 2+(y−4) 2=65 ⇒ (x−2) 2+(y−4) 2=(65)2 Which is of … phytyl decanoate

"WebNov 23, 2016 · Intersection points are (1,-1) and (4,2) and tangents are x+2y+1=0 and 2x+y=10 x^2+y^2-4x-2y=0 an be written as (x-2)^2+(y-1)^2=5 and hence is a circle with center at (2,1) and radius sqrt5. For finding intersection point between x^2+y^2-4x-2y=0 and line y=x-2, we can put y=x-2 in the equation x^2+y^2-4x-2y=0. Doing this, we get x^2+(x … " - Radius of the circle x2+y2-4x+2y-45 0 is

Radius of the circle x2+y2-4x+2y-45 0 is

What is the center and radius of x^2+4x+y^2-6y-3=0? Socratic

WebMar 22, 2024 · Find the center and the radius of the circle x 2 + y 2 - 12x - 18y - 27 = 0. ... The line 3x − 4y = λ touches the circle x2 + y2 − 4x − 8y − 5 = 0, then the value of λ = _____ ... the angles of depression of the banks on opposite sides of the river are 30° and 45° respectively. If the bridge is at a height of 3 m from the banks ... WebExpert Answer. Transcribed image text: For the equation x2 + y2 - 4x - 2y – 31 = 0. do the following. (a) Find the center (h,k) and radius r of the circle. (b) Graph the circle. (c) Find the intercepts, if any. (a) The center is 1 (Type an ordered pair.) The radius is re (b) Use the graphing tool to graph the circle.

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WebNov 1, 2016 · is the standard form for the equation of a circle with center #(color(red)a,color(blue)b)# and radius #color(magenta)r#. Lets try to convert the given equation: #color(white)("XXX")x^2+y^2-6x-4y-12=0# into the standard form for the equation of a circle. Group the #x# and #y# terms separately and "move" the constant to the right … WebGiven: x 2 + y 2 - 4x +2y - 31 = 0 are equation of circle with centres C 1 and radius r 1 By comparing the equation of the circle with the equation ax 2 + ay 2 + 2gx + 2fy + c = 0, we …

WebA: Givenx2+y2=9To find Center and radius of above equation Q: Find the point(s) of intersection of the line y=7x-42 and the circle with equation x2+y2-4x+6y=12. A: Click to see the answer Q: Draw a circle with an equation of x2+y2+4y=5 A: First we add 4 to both sides and complete the square of y term. WebClick here👆to get an answer to your question ️ Find the centre and radius of the circle x^2 + y^2 - x + 2y - 3 = 0 . ... Find the centre and radius of the circle x 2 + y 2 − x + 2 y − 3 = 0. Medium. Open in App. Solution. Verified by Toppr. given equation is x 2 + y 2 ...

WebJan 17, 2024 · radius = 2 Explanation: The standard equation of a circle with centre (a,b), and radius r is: (x − a)2 +(y −b)2 = r2 so for : x2 + y2 +4x − 2y = − 1 we will have to … WebJun 1, 2024 · Explanation: x2 +4x + y2 −6y − 3 = 0 or. x2 +4x + 4 + y2 −6y +9 = 4 + 9 + 3 or. (x +2)2 + (y −3)2 = 42 The center-radius form of the circle. equation is (x– h)2 + (y– k)2 = r2, with the center being at. the point (h,k) or ( − 2,3) and the radius being r = 4. So, center is at ( − 2,3) and radius is 4 unit. graph {x^2+4x+y^2-6 y-3 ...

WebCalculus. Find the Center and Radius x^2+y^2-4x+2y=0. x2 + y2 − 4x + 2y = 0 x 2 + y 2 - 4 x + 2 y = 0. Complete the square for x2 −4x x 2 - 4 x. Tap for more steps... (x−2)2 −4 ( x - 2) 2 - …

WebThe standard equation for a circle centred at (h,k) with radius r is (x-h)^2 + (y-k)^2 = r^2 So your equation starts as ( x + 1 )^2 + ( y + 7 )^2 = r^2 Next, substitute the values of the given point (2 for x and 11 for y), getting 3^2 + 18^2 = r^2, so r^2 = 333. The final equation is (x+1)^2 + (y+7)^2 = 333 Hope this helps! ( 9 votes) Flag phytylatedWebAdd 0 0 and 4 4. x2 + (y−2)2 = 4 x 2 + ( y - 2) 2 = 4. This is the form of a circle. Use this form to determine the center and radius of the circle. (x−h)2 +(y−k)2 = r2 ( x - h) 2 + ( y - k) 2 = r 2. Match the values in this circle to those of the standard form. The variable r r represents the radius of the circle, h h represents the x ... phytyl acetateWebHInt: 2x^2+x(2y)+y^2-2y+2=0 As x is real, the discriminant must be \ge0 (2y)^2-8(y^2-2y+2)\ge0\iff0\ge-4(y-2)^2\iff(y-2)^2\le0 But as y is real, (y-2)^2\ge0 How do you find the … too white crew 2022WebSep 3, 2012 · You're trying to make this look like the equation for a circle which has the two square binomials set equal to the radius. Anyway, since both coefficients are 2, simply divide the whole thing by two. x 2 + 4x + (____) + y 2 - 6y + (____) = 12 Now look at the x term, 4x. too wet to tillWebGiven circle is x 2+y 2−4x+2y−45=0this is of the form x 2+y 2+2gx+2fy+c=0, where(2g=−4;2f=2)⇒(g=−2;f=1),c=−45radius = g 2+f 2−c= (−2) 2+1 2+45= 50=5 2. phytx fact sheetWebMar 30, 2024 · Transcript. Ex 11.1, 7 Find the centre and radius of the circle x2 + y2 – 4x – 8y – 45 = 0 Given x2 + y2 – 4x – 8y – 45 = 0. We need to make this in form (x – h)2 + (y – … phytyl diphosphateWebMar 29, 2024 · Answer: The center of the circle; (2, -1) The radius of the circle; r = 4 Step-by-step explanation: The first step is to complete the square on both x and y; x^2 + y^2 -4x + … too white abbigliamento