WebAug 14, 2024 · In an isosceles ∆ABC, if AC = BC and AB 2 = 2AC 2, then find ∠C. Solution: AB 2 = 2AC 2 (Given) AB 2 = AC 2 + AC 2 AB 2 = AC 2 + BC 2 (∵ AC = BC) Hence AB is the hypotenuse and ∆ABC is a right angle A. So, ∠C = 90° Question 9. The length of the diagonals of a rhombus are 16 cm and 12 cm. Find the length of side of the rhombus. … WebIn the figure, if BP CQ and AC= BC, then the measure of x is Solution In the figure, AC=BC, BP CQ ∵ BP CQ ∴ ∠P BC =∠QCD ⇒ 20∘+∠ABC =70∘ ⇒ ∠ABC =70∘ −20∘ =50∘ ∵ BC= AC ∴ ∠ACB=∠ABC (Angles opposite to equal sided) = 50∘ Now in ΔABC, Ext. ∠ACD=∠B+∠A ⇒ x+70∘ = 50∘+50∘ ⇒x+70∘ =100∘ ∴ x= 100∘−70∘ =30∘ Suggest Corrections 33 Similar …
In the given figure, if DE BC, then find the length of AC
WebApr 11, 2024 · Genome sequencing, assembly, and annotation. The genome size of the haploid line (Supplementary Fig. 1b, d) was estimated to be approximately 8.47~8.88 Gb by K-mer analysis using 1070.20 Gb clean short reads (Supplementary Fig. 2a–d and Supplementary Tables 1 and 2), which was slightly smaller than the size estimated by … WebAug 27, 2024 · Best answer The given figure: To find: area (ADE) : area (DECB) Given, DE BC, DE = 6 cm and BC = 12 cm In ∆ABC and ∆ADE, ∠ABC = ∠ADE [corresponding angle] ∠ACB = ∠AED [corresponding angle] And ∠A = ∠A [common side] ∴ ∆ABC ∼ ∆AED [by AAA similarity criterion] Then, mda toowoomba office
RD Sharma Solutions for Class 10 Chapter 4 Triangles Exercise 4.2 …
WebAnswer The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the side BC. Prove that DF × EF = FB × FA. 1489 Views Answer … WebIn given ΔABC points D and E are mid points of AB and AC and also BC = 6 cm then find DE. asked Mar 23, 2024 in Triangles by AdvaitMogarkar (43.7k points) triangles; class-10; … WebAlso, as AC = BC Using the property,”angles opposite to equal sides are equal”, we get ∠ABC = ∠CAB ∠ABC = 20° + x Further, using the property, “an exterior angle is equal to the sum of the two opposite interior angles” In ΔABC ext. ∠C = ∠CAB + ∠ABC 70° + x = 20° + x + 20° + x 70° + x = 40° + 2x 70° - 40° = 2x - x x = 30° Thus, x = 30° mdatp health issues