If the 5th term of gp is 2
Web2 dagen geleden · Austin, Circuit of the Americas 151K views, 5.3K likes, 496 loves, 402 comments, 321 shares, Facebook Watch Videos from MotoGP: Four years ago, a new... WebAnswer (1 of 5): Let a be the first term and r be the common ratio of the geometric progression, then a r^2 = 5\qquad a r^5 = -40\implies \dfrac{a r^5}{a r^2} = -\dfrac{40}{5} = -8 \implies r^3 = - 8\implies r = -2 a r^5 = -40\implies a (-2)^5 = …
If the 5th term of gp is 2
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Web18 nov. 2024 · The seventh term of a GP is 4 times the 5th term. What will be the first term when its 4th term is 40? asked Nov 27, 2024 in Mathematics by Annu03 (53.2k points) airthmetic progressions; 0 votes. 1 answer. If 4 times the 4th term of an AP is equal to 18 times its 18th term then find its 22nd term. Web24 feb. 2024 · The third term of a geometric progressiom is nine times the first term.if the second term is one-twenty fourth the fifth term.find the fourth term.ar^2=9a. r=sqr of 9 r=3.pls teach me how to get the first term and i can get the 4th term myself; The third term of an ap is 10 more than the first term while the fifth term is 15 more than the ...
Web13 apr. 2024 · The sum of the first 5 terms of a GP is 61. If the 5th term is 81 solve the value of the common ratio. asked by john April 13, 2024 1 answer just solve the system a (r^5-1)/ (r-1) = 61 ar^4 = 81 Hint: 81 = 3^4 answered by Steve April 13, 2024 Answer this Question Still need help? WebThe fifth term of a G.P. is 81 and the second term is 24; find the series. Easy Solution Verified by Toppr a,ar,ar 2,ar 3,...........,ar n−1 be the G.P. with common ratio r And let a …
WebIf the fifth term of a G.P. is 2, then write the product of its 9 terms. Solution Here, a2 = 2 Nine terms of a G.P. are, a r4, a r3, a r2, a r,a,ar,ar2,ar3,ar4 ⇒ a= 2 Then, a r4× a r3× a … WebAnswer: in a GP the nth term is a(r)^n-1 Given 2nd term is 2 and 5th term is 2/27 ie., ar = 2 and ar^4 = 2/27 i.e, ar^4/ar = (2/27)/ 2 ie., r^3 = 1/27 i.e, r = 1/3 If we put the value of r = …
WebThe GP is generally represented in form a, ar, ar 2.... where 'a' is the first term and 'r' is the common ratio of the progression. The common ratio can have both negative as well as …
Web17 feb. 2024 · If the 5th term of a G.P is 16 and the 10th term is 1/2,then the 15th term is Get the answers you need, now! Popsicle6312 Popsicle6312 17.02.2024 Math Secondary School answered • expert verified If the 5th term of a G.P is 16 and the 10th term is 1/2,then the 15th term is See answers legendary mythical eternalWebIf the 5th term of a G.P is 2, then the product of first 9 terms is Q2. Three distinct numbers x, y, z form a G.P. in that order and the number x + y, y + z, z + x form an A.P. in that order. legendary mythic pokemonWebThus 5th term = (2/5)* (5/2)^4 = (5/2)^3=125/8 More answers below If the 2nd, 5th and 9th terms of a non-constant AP and GP, then what is the common ratio of this GP? In a certain GP, the second term is 32 and the fifth term is 4. The sum of first 4 terms is k% of the sum of infinity. The value of kis? legendary mythical pokemon listWeb17 nov. 2024 · Concept: If a is the first term and r is the common ratio of a GP then the nth term of GP is given by: an = arn - 1 Calculation: Given: 3rd, 8th and 13th ter. Get Started. Exams. SSC Exams. Banking Exams. Teaching Exams. ... If the 5th term of a G.P is 2, then the product of first 9 terms is. Q3. What is the value of 22 + 42 + 62 ... legendary nails banburyWeb24 jul. 2024 · Common ratio, r = 2, ar4 = 80 16a = 80 a = 5 The required GP is of the form a, ar, ar2 , ar3 , ar4…. First term of GP, a = 5 Second term of GP, ar = 5 x 2 =10 Third term of GP, ar2 = 5 x 22 = 20 Fourth term of GP, ar3 = 5 x 23 = 40 Fifth term of GP, ar4 = 5 x 24 = 80 And so on... The required GP is 5, 10, 20, 40, 80… ← Prev Question Next … legendary mythical placesWeb22 mrt. 2024 · We know that an = arn 1 where an = nth term of GP n is the number of terms a is the first term r is the common ratio Here, common ratio r = 2 & 8th term is 192 i.e. a8 = 192 Putting an = 192, r = 2 and n = 8 in an 192 = a 2^ (8 1) 192 = a 27 192/27 = a a = 192/27 Now we need to find 12th term, we use the formula an = arn 1 Putting n = 12 , a … legendary nails chicagoWeb10 jun. 2024 · 512 A term in GP is given by T_n=ar^(n-1) where n is the nth term Your fifth (5) term is equal to 2 T_5=ar^(5-1)=2 T_5=ar^4=2 So, now you want to find the product of 9 terms ie atimesar timesar^2times...timesar^8 = a^9r^36 = (ar^4)^9 = 2^9 = 512 Basically what I did above was go: ... legendary nails and spa pearland