How to solve cos2x sinx
WebThen recall that cos ( 2 x) = 1 − 2 sin 2 ( x) to give: 3 sin ( x) − 4 sin 3 ( x) = 1 − 2 sin 2 ( x) This is a cubic in sin ( x). For simplicity write y = sin ( x) to get: − 4 y 3 + 2 y 2 + 3 y − 1 = 0 − ( y − 1) ( 4 y 2 + 2 y − 1) = 0 So sin ( x) = 1 or sin ( x) = − 1 ± 5 4 So x = π 2 or x = π 10, 9 π 10, 13 π 10, 17 π 10 Share Cite Follow http://mathcentral.uregina.ca/QQ/database/QQ.09.04/kris1.html
How to solve cos2x sinx
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WebBy using the double-angle formula, you can solve sinx+cos2x=0 for x. The double-angle formula states that sin 2x = 2sin xcos x and cos 2x = cos2 x − sin2 x. Plugging these formulas in to the equation yields: 2sinxcosx + cos2 x − sin2 x = 0. WebHINT: Let y = 2+cosx2+sinx Use Weierstrass substitution , to form a Quadratic Equation in tan 2x As tan 2x is real, the discriminant must be ≥ 0 This should give ... More Items …
WebFree Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators step-by-step WebJul 29, 2024 · cos 2 ( x) − sin 2 ( x) = 1 = cos 2 ( x) + sin 2 ( x) we must have sin 2 ( x) = 0 so that x ∈ { n π: n ∈ Z } – MathematicsStudent1122 Jul 29, 2024 at 1:44 1 Answers below …
WebAug 5, 2024 · sin(3x) = 2sin(3x / 2)cos(3x / 2) then. cos(x) − sin3x = cos2x 2sin(x / 2)sin(3x / 2) = 2sin(3x / 2)cos(3x / 2) therefore we have two cases. 1. sin(3x / 2) = 0 3 2x = kπ x = 2 … WebTrigonometry Solve for x sin (2x)+cos (2x)=1 sin(2x) + cos(2x) = 1 sin ( 2 x) + cos ( 2 x) = 1 Subtract 1 1 from both sides of the equation. sin(2x)+cos(2x)−1 = 0 sin ( 2 x) + cos ( 2 x) - 1 = 0 Simplify the left side of the equation. Tap for more steps... 2sin(x)cos(x)−2sin2(x) = 0 2 sin ( x) cos ( x) - 2 sin 2 ( x) = 0
WebJul 29, 2024 · cos 2 ( x) − sin 2 ( x) = 1 = cos 2 ( x) + sin 2 ( x) we must have sin 2 ( x) = 0 so that x ∈ { n π: n ∈ Z } – MathematicsStudent1122 Jul 29, 2024 at 1:44 1 Answers below and comment above are all correct. But I'd like to warn you: no, it's not possible to "divide" by 2 the way you did.
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